The emf of the following cells are ag/ag+

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Webসঠিক উত্তর : a এবং b উভয়ই অপশন ১ : cuo+h2=cu+h2o অপশন ২ : feo+co=fe+co2 অপশন ৩ : h2s+ci2=s+2hci অপশন ৪ : a এবং b উভয়ই WebCalculate the emf of the following cell at 25∘C : Ag(s) Ag+(10−3M) Cu2+(10−1M) Cu(s) Given E∘ cell = +0.46 V and log 10n = n. Solution For the given cell, the redox reaction is …

Calculate the emf of the following cell at 25∘ C : Ag s

WebExplain the following: (i) Nernst Equation. (ii) Aqua regia. Hard. View solution > How does cell EMF depend on increasing the concentration of KOH ? Hard. View solution > How will concentration of Zn 2 + ions and Ag + ions be affected when the cell functions? Hard. View solution > How will the concentration of Zn 2 + ions and Ag + ions be ... WebMar 8, 2024 · Ecell = + 0.49xV Explanation: The cell diagram implies that we are under standard conditions where we have unit concentration which is then increased by a factor … margelle gris anthracite

Solved A voltaic cell utilizes the following reaction: Al(s) - Chegg

WebThe standard potential of Ag/Ag+half cell is +0.80 V and Zn/Zn2+ is -0.76 V. Q3.What is the Emf of the following cell at 25 0 C. Zn 2+ /Zn(0.2M) //Ag+(0.002 M)/Ag(s) WebThe emf of the following cells are:Ag Ag +1 M Cu 2+1 M Cu E cell = 0.46 V andZn Zn 2+1 M Cu 2+1 M Cu E cell =+1.10 VThen the emf of the cell Zn Zn 2+1 M Ag +1 M Ag is:A. 0.64 VB. 1.1 VC. 1.56 VD. 0.64 V. Login. Study Materials. NCERT … margely shialer

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WebScience Chemistry n the cell Pt Fe3+ ( a = 1), Fe2+ (a = 1) Ag+ (a =1) Ag The standard emf at 298 K for the half-cell Ag+ Ag is 0.80 V, and for Pt Br2 , Br− is 0.771 V. Calculate the equilibrium constant for the cell reaction at 298 K. [3.2] … WebDividing both sides of this equation by − nF, Ecell = E ∘ cell − (RT nF)lnQ. Equation 20.6.2 is called the Nernst equation, after the German physicist and chemist Walter Nernst (1864–1941), who first derived it. The Nernst equation is arguably the most important relationship in electrochemistry. margem consig webWebDec 10, 2024 · From the table of standard reduction potentials, you find (3) Li + + e − → Li E ∘ = − 3.045 (4) Ag → Ag + + e − E ∗ = − 0.799 According to the convention of the cell, the … kurtis blow real name

"WebA voltaic cell utilizes the following reaction: Al (s) + 3Ag+ (aq) Al3+ (aq) + 3Ag (s) What is the effect on the cell emf of each of the following changes? A Water is added to the anode compartment, diluting the solution. (a)The cell emf will increase. (b)The cell emf will decrease. (c)The cell emf will remain the same. " - The emf of the following cells are ag/ag+

The emf of the following cells are ag/ag+

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WebThe EMF of the Daniell cell is 1.1V . The external EMF to be applied for the following reaction to take place in it is: C u ( s ) + Z n ( a q ) 2 + → C u ( a q ) 2 + + Z n ( s ) Weba) Calculate the emf of the following cell Zn/Zn2+ (0.1M) II Ag+ (0.2M)/Ag; Given E°Zn2+ Zn = -0.76 V and EºAgt/Ag = +0.8 V 2+ + b) A Cu rod is placed in 0.01 M CuSO4 solution at 298K. Calculate the potential of the electrode assuming that salt is dissociated to 90 % at this dilution. Given E° for Cu2+/Cu = 0.34 V

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WebMaths-17 12th - Free download as PDF File (.pdf), Text File (.txt) or read online for free. Class : XII PART TEST- 2 Time : 3 hour Max. Marks : 60 INSTRUCTIONS 1. The question paper contain pages and 3-parts. Part-A contains 6 objective question , Part-B contains 2 questions of "Match the Column" type and Part-C contains 4 subjective type questions. WebThe emf (E^∘) of the following cells are: Ag/ Ag^+ (1 M)∥ Cu^2 + (1 M) Cu; E^∘ = - 0.46 volt Zn/Zn^2 + (1 M) ∥ Cu^2 + (1 M) Cu; E^∘ = + 1.10 volt Calculate the emf of the cell: Zn Zn^2 + (1 M)∥ Ag^+ (1 M) Ag . Class 12. >> Chemistry. >> Electrochemistry. >> Nernst Equation.

WebIn which of the following cases blood cells will shrink: (a)when placed in water containing more than 0.9% (mass/ volume) NaCl ... E°Ag+/Ag= 0.8 0 v) 5. A copper-silver cell is set up. The copper ion concentration is 0.10 M. The ... What is the emf a cell when the cell reaction attains equilibrium? WebOct 27, 2024 · Calculate the EMF of the concentration cell at 298 K: Ag/Ag^+ (0.005 M)//Ag^+ (0.5 M)/Ag.

WebCalculate the emf of the following cell at 25∘ C : Ag s Ag +10 3 M Cu 2+10 1 M Cu s Given Ecell ∘=+0.46 V and log 10 n = n. Login. Study Materials. NCERT Solutions. NCERT Solutions For Class 12. ... Q. Calculate the emf of the following cell at 25 o C A g (s) ... WebStudy with Quizlet and memorize flashcards containing terms like Electrolytic cells utilize electrical energy to drive non-spontaneous redox reactions. (true/false), Which one of the following is not a redox reaction?, Consider the following redox equation Mn(OH)2(s) + MnO4-(aq) ® MnO42-(aq) (basic solution) When the equation is balanced with smallest …

WebCalculate the emf of the concentration cell at 298 K. Ag / Ag+ (0.002 M) // Ag+ (0.5 M)/Ag. What will be the potential of above cell, when the. concentration silver ions is changed from 0.002 M to 0.005 M at the same

WebMay 9, 2024 · \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1 ... margem consig web bombeiroWebNov 8, 2024 · Answer to Question #143212 in Physical Chemistry for Kyrie. Answers >. Chemistry >. Physical Chemistry. Question #143212. Calculate the standard emf of a cell that uses Ag/Ag+ and Al/Al3+ half-cell reactions. Write the cell reaction that occurs under standard-state conditions. margelle therapieWebJun 29, 2024 · Where, Ecell = the EMF of the cell, Eo = Standard EMF of cell, [ Mg2+ ] = Concentration of Mg, [ Ag+] = Concentration of Ag, n = ion charge ( moles of electrons ). We can given that, The EMF of the cell is = 2.96 V, Concentration of Mg [ Mg2+ ] = 0.130 M . Concentration of Ag [ Ag+ ] = 1.0 x 10-4 M. We can write the Cell reaction as, Mg + 2 Ag+ ... margem clear