WebFind the prime factorization of 18 18 = 2 × 3 × 3 Find the prime factorization of 45 45 = 3 × 3 × 5 Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM: LCM = 2 × 3 × 3 × 5 LCM = 90 MathStep (Works offline) Download our mobile app and learn how to find LCM of upto four numbers in your own time: WebThere are 6 common factors of 36 and 90, that are 1, 2, 3, 6, 9, and 18. Therefore, the highest common factor of 36 and 90 is 18. HCF of 36 and 90 by Euclidean Algorithm As per the Euclidean Algorithm, HCF (X, Y) = HCF (Y, X mod Y) where X > Y and mod is the modulo operator. Here X = 90 and Y = 36 HCF (90, 36) = HCF (36, 90 mod 36) = HCF …
Highest Common Factor - GCSE Maths - Steps, Examples
WebApr 3, 2024 · The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36. The factors of 45 are 1, 3, 5, 9, 15, 45. The common factors of 36 and 45 are 1, 3, 9. The greatest common factor of 36 … WebFeb 28, 2024 · This paper aims to provide a better understanding regarding the effects of shot peening (SP), surface mechanical attrition treatment (SMAT), laser shock peening (LSP), surface mechanical rolling treatment (SMRT), and ultrasonic nanocrystal surface modification (UNSM) on the fatigue properties of metals in high-cycle fatigue (HCF) and … dr neal sidney bc
HCF Using Euclid
WebThere are three commonly used methods to find the HCF of 45 and 180. By Long Division By Listing Common Factors By Prime Factorisation If the HCF of 180 and 45 is 45, Find its LCM. HCF (180, 45) × LCM (180, 45) = 180 × 45 Since the HCF of 180 and 45 = 45 ⇒ 45 × LCM (180, 45) = 8100 Therefore, LCM = 180 WebHCF of 27 and 45 by Euclidean Algorithm As per the Euclidean Algorithm, HCF (X, Y) = HCF (Y, X mod Y) where X > Y and mod is the modulo operator. Here X = 45 and Y = 27 HCF (45, 27) = HCF (27, 45 mod 27) = HCF (27, 18) HCF (27, 18) = HCF (18, 27 mod 18) = HCF (18, 9) HCF (18, 9) = HCF (9, 18 mod 9) = HCF (9, 0) WebQ1) Find the HCF of the following numbers : (i) 18, 48 (ii) 30, 42 (iii) 18, 60 (iv) 27, 63 (v) 36, 84 (vi) 34, 102 (vii) 70, 105, 175 (viii) 91, 112, 49 (ix) 18, 54, 81 (x) 12, 45, 75 Answer: SOLUTION: i) 18,48 18=2\times3\times3 18 = 2× 3×3 48=2\times2\times2\times2\times3 48 … dr neal shirey griffin ga